If the density of ocean water at a depth of 10,000 m is 1.071 g/mL and if 25.0 g of water at that depth contains 190 mg of KCl, what is the molarity of KCl?

 If the density of ocean water at a depth of 10,000 m is 1.071 g/mL and if 25.0 g of water at that depth contains 190 mg of KCl, what is the molarity of KCl?

(190 mg) × (1 g/1000 mg) × (1 mol/74.55 g) = 0.002549 mol KCl (25.0 g) × ( 1 mL/1.071 g) × (1 L/1000 mL) = 0.0233 L

Molarity = (0.002549 mol/0.0233 L) = 0.109 M

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